This page was exported from Braindump2go Free Exam Dumps with PDF and VCE Collection [ https://www.mcitpdump.com ] Export date:Fri Apr 19 3:28:14 2024 / +0000 GMT ___________________________________________________ Title: New Released Microsoft 70-433 Dumps PDF&VCE Free Download from Braindump2go (121-130) --------------------------------------------------- Real Latest 70-433 Exam Questions Updated By Official Microsoft Exam Center! Braindump2go Offers 70-433 Dumps sample questions for free download now! You also can visit our website, download our premium Microsoft 70-433 Exam Real Answers, 100% Exam Pass Guaranteed! Exam Code: 70-433Exam Name: TS: Microsoft SQL Server 2008, Database DevelopmentCertification Provider: MicrosoftKeywords: 70-433 Exam Dumps,70-433 Practice Tests,70-433 Practice Exams,70-433 Exam Questions,70-433 PDF,70-433 VCE Free,70-433 Book,70-433 E-Book,70-433 Study Guide,70-433 Braindump,70-433 Prep Guide QUESTION 121You create and populate two tables by using the following Transact-SQL statements: CREATE TABLE CurrentStudents (LastName VARCHAR(50), FirstName VARCHAR(50), Address VARCHAR(100), Age INT); INSERT INTO CurrentStudents VALUES ('Fritz', 'David', '181 Kline Street', 14) ,('Reese', 'Paul' , '4429 South Union', 14) ,('Brown', 'Jake' ,  '5401 Washington Ave',14)  ,('Smith', 'Tom' ,  '124 Water St',  14)  ,('Holtz', 'Mary' ,  '984 Mass Ct',  14)  ,('Robbins', 'Jan' ,  '4449 Union Ave',  14)  ,('Larsen', 'Frank' ,  '5812 Meadow St',  14)  ,('Bishop', 'Cathy' ,  '14429 Skyhigh Ave',  14)  ,('Francis', 'Thomas' , '15401 120th St', 14) CREATE TABLE NewYearRoster(LastName VARCHAR(50), FirstName VARCHAR(50), Address VARCHAR(100), Age INT); INSERT INTO NewYearRoster VALUES ('Fritz', 'David', '181 Kline Street', 15) ,('Reese', 'Paul', '1950 Grandview Place', 15) ,('Adams', 'Wilbur', '4231 W. 93rd', 15) ,('Adams', 'Norris', '100 1st Ave', 15) ,('Thomas', 'Paul', '18176 Soundview Dr', 15) ,('Linderson', 'Danielle', '941 W. 37 Ave', 15) ,('Moore', 'Joshua', '2311 10st Ave', 15) ,('Dark', 'Shelby', '1987 Fifth Ave', 15) ,('Scharp', 'Mary', '1902 W. 303rd', 15) ,('Morris', 'Walt', '100 12st St', 15); You run the following MERGE statement to update, insert and delete rows in the CurrentStudents table MERGE TOP (3) CurrentStudents AS T USING NewYearRoster AS S ON S.LastName = T.LastName AND S.FirstName = T.FirstName WHEN MATCHED AND NOT (T.Age = S.Age OR T.Address = S.Address) THEN UPDATE SET Address = S.Address, Age = S.Age WHEN NOT MATCHED BY TARGET THEN INSERT (LastName, FirstName, Address, Age) VALUES (S.LastName, S.FirstName, S.Address, S.Age) WHEN NOT MATCHED BY SOURCE THEN DELETE; You need to identify the total number of rows that are updated, inserted, and deleted in the CurrentStudent table. Which total number of rows should you choose? A.    0 B.    3 C.    6 D.    9 Answer: B QUESTION 122You are writing a query that returns a list of products that have grossed more than $10,000.00 during the year 2007. You need to insert the following filter expression into the query. SUM([Order Details].UnitPrice * [Order Details].Quantity) > 10000 Into which clause should you insert this expression? A.    ON B.    WHERE C.    HAVING D.    GROUP BY Answer: C QUESTION 123You have a table named Sales. You are tasked to list products that have been sold to less than ten customers. You need to write a query to achieve the task. Which Transact-SQL statement should you use? A.    SELECT ProductID, COUNT(*) AS CustomerCount FROM Sales GROUP BY ProductID, CustomerID HAVING COUNT(*) < 10; B.    SELECT ProductID, COUNT(DISTINCT CustomerID) AS CustomerCount FROM Sales GROUP BY ProductID HAVING COUNT(DISTINCT CustomerID) < 10; C.    SELECT ProductID, CustomerID, COUNT(DISTINCT CustomerID) AS CustomerCount FROM Sales GROUP BY ProductID, CustomerID HAVING COUNT(DISTINCT CustomerID) < 10; D.    SELECT * FROM (SELECT ProductID, RANK() OVER (ORDER BY CustomerID DESC) AS Rnk FROM Sales) s WHERE s.Rnk <= 10; Answer: B QUESTION 124You have two tables named Customers and Orders. for customers that have placed at least one order, you need to produce a list of customer names and the number of orders for each customer. Which query should you use? A.    SELECT c.CustomerName, SUM(o.OrderID) AS [OrderCount] FROM Customers c JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerName B.    SELECT COUNT(o.OrderId) AS [OrderCount] FROM CUSTOMERS c JOIN ORDERS o ON c.CUSTOMERID = o.CUSTOMERID C.    SELECT c.CustomerName, COUNT(o.OrderID) AS [OrderCount] FROM Customers c JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerName HAVING COUNT(o.OrderID) > 1 D.    SELECT c.CustomerName, COUNT(o.OrderId) AS [OrderCount] FROM Customers c JOIN Orders o ON c.CustomerId = o.CustomerId GROUP BY c.CustomerName Answer: D QUESTION 125You have a table named Products. The table contains a column named Color. You need to write a Transact-SQL statement that calculates the percentage of products of each product color. Which Transact-SQL statement should you use? A.    SELECT Color COUNT(*) OVER(PARTITION BY Color) / (COUNT(*) * 1.0) AS PercentColor FROM Products GROUP BY Color; B.    SELECT Color COUNT(*) OVER() / (COUNT(*) * 1.0) AS PercentColor / (COUNT(*) * 1.0) AS PercentColor FROM Products GROUP BY Color; C.    SELECT Color, (COUNT(*) * 1.0)/ COUNT(*) OVER() AS PercentColor FROM Products GROUP BY Color; D.    SELECT Color, COUNT(*) * 1.0) / COUNT(*) OVER(PARTITION BY Color) AS PercentColor FROM Products GROUP BY Color; Answer: C QUESTION 126You have two tables named SalesPerson and SalesTerritory. You need to create sample data by using a Cartesian product that contains the data from the SalesPerson and SalesTerritory tables. Which code segment should you use? A.    SELECT p.SalesPersonId, t.Name AS [Territory] FROM Sales.SalesPerson p FULL JOIN Sales.SalesTerritory t ON p.TerritoryId = t.TerritoryId B.    SELECT p.SalesPersonId, Name AS [Territory] FROM Sales.SalesPerson p INNER JOIN Sales.SalesTerritory t ON p.TerritoryId = t.TerritoryId C.    SELECT p.SalesPersonId, t.Name AS [Territory] FROM Sales.SalesPerson p CROSS JOIN Sales.SalesTerritory t WHERE p.TerritoryId = t.TerritoryId D.    SELECT p.SalesPersonId, t.Name AS [Territory] FROM Sales.SalesPerson p CROSS JOIN Sales.SalesTerritory t; Answer: D QUESTION 127You have a table named Employees. You want to identify the supervisor to which each employee reports. You write the following query. SELECT e.EmloyeeName AS [EmployeeName], s.EmployeeName AS [SuperVisorName] FROM Employees e You need to ensure that the query returns a list of all employees and their respective supervisor. Which join clause should you use to complete the query? A.    LEFT JOIN Employees s ON e.ReportsTo = s.EmployeeId B.    RIGHT JOIN Employees s ON e.ReportsTo = s.EmployeeId C.    INNER JOIN Employees s ON e.EmployeeId = s.EmployeeId D.    LEFT JOIN Employees s ON e.EmployeeId = s.EmployeeId Answer: A QUESTION 128You have a table named Subcategories that contains subcategories for socks, vests and helmets. You have another table named Products that contains products only from the subcategories socks and vests. You have the following query: SELECT s.Name, p.Name AS ProductName FROM Subcategories s OUTER APPLY (SELECT * FROM Products pr WHERE pr.SubcategoryID = s.SubcategoryID) p WHERE s.Name IS NOT NULL; You need to predict the results of the query. What results should the query produce? A.    Name ProductName---------- -------------------- Socks Mountain Bike Socks,Socks Mountain Bike Socks,Socks Racing Socks, M Socks Racing Socks, L Vests Classic Vest, S Vests Classic Vest, M Vests Classic Vest, L B.    Name ProductName ---------- --------------------Socks Mountain Bike Socks, Socks Mountain Bike Socks,Socks Racing Socks, M Socks Racing Socks, L Vests Classic Vest, S Vests Classic Vest, M Vests Classic Vest, L Helmets NULL C.    Name ProductName ---------- --------------------Socks Mountain Bike Socks,Socks Mountain Bike Socks,Socks Racing Socks, M Socks Racing Socks, L Vests Classic Vest, S Vests Classic Vest, M Vests Classic Vest, L Helmets NULL NULL NULL D.    Name ProductName ---------- --------------------Socks Mountain Bike Socks,Socks Mountain Bike Socks,Socks Racing Socks, M Socks Racing Socks, L Vests Classic Vest, S Vests Classic Vest, M Vests Classic Vest, L NULL Mountain Bike Socks,NULL Mountain Bike Socks,NULL Racing Socks, M NULL Racing Socks, L NULL Classic Vest, S NULL Classic Vest, M NULL Classic Vest, L Helmets NULL NULL NULL Answer: B QUESTION 129You have two tables named dbo.CurrentProducts and dbo.ArchiveProducts. You have the following query: SELECT ProductID, Name FROM dbo.CurrentProducts UNION ALL SELECT ProductID, Name FROM dbo.ArchiveProducts; You need to predict the list of products that the query will produce. Which list of products should the query return? A.    Products that appear in dbo.CurrentProducts or dbo.ArchiveProducts but not in both. B.    Products that have a matching ProductID and Name in dbo.CurrentProducts or dbo.ArchiveProducts. C.    Products that appear in dbo.CurrentProducts or dbo.ArchiveProducts. Products that appear in both tables are listed only once. D.    Products that appear in dbo.CurrentProducts or dbo.ArchiveProducts. Products that appear in both tables are listed multiple times. Answer: D QUESTION 130You have two tables named Products and NewProducts that have identical structures. You have the following query (Line numbers are included for reference only): 01     SELECT Product, Description 02     FROM dbo.Products 03     ........04     SELECT Product, Description 05     FROM dbo.NewProducts You need to choose the appropriate Transact-SQL operator to display rows that exist in both tables. Which Transact-SQL operator should you insert in line 03? A.    UNION B.    EXCEPT C.    UNION ALL D.    INTERSECT Answer: D Braindump2go Offers PDF & VCE Dumps Download for New Released Microsoft 70-433 Exam! 100% Exam Success Guaranteed OR Full Money Back Instantly! http://www.braindump2go.com/70-433.html --------------------------------------------------- Images: --------------------------------------------------- --------------------------------------------------- Post date: 2015-07-24 08:14:40 Post date GMT: 2015-07-24 08:14:40 Post modified date: 2015-07-24 08:14:40 Post modified date GMT: 2015-07-24 08:14:40 ____________________________________________________________________________________________ Export of Post and Page as text file has been powered by [ Universal Post Manager ] plugin from www.gconverters.com